(Solved Homework): write a program that uses the bisection method to find the root of a function, f(x)=x-5(1-e^(-x))…

write a program that uses the bisection method to find the root of a function, f(x)=x-5(1-e^(-x))

System.out.println(“Enter left bound.”);
x1= input.nextDouble();
System.out.println(“Enter right bound”);
xr = input.nextDouble();
while(Math.abs(xr-x1)>err)

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{
xm=(xr+x1)/2;
if(func(x1)*func(xm)<0)
xr=xm;
else
x1=xm;
}
System.out.println(xm);

Expert Answer

public class Bisection {

private static void doBisection(double err) {
Scanner input = new Scanner(System.in);
System.out.println(“Enter left bound.”);
double x1 = input.nextDouble();
System.out.println(“Enter right bound”);
double xr = input.nextDouble();
double xm = 0;
while (Math.abs(xr – x1) > err) {
xm = (xr + x1) / 2;
if (func(x1) * func(xm) < 0) {
xr = xm;
} else {
x1 = xm;
}
}
System.out.println(xm);
}

private static double func(double x) {
return x – 5 * (1 – Math.exp(-x));
}

public static void main(String[] args) {
doBisection(1e-8);
}

}

I have used the code you have provided to proceed. The bisection method you provided will work only with increasing function, i.e. f(left bound) <= f(right bound). If you want anything more, please let me know through commens. I shall be glad to help you.

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