a) The correct network diagram for this project is A
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b) To find the critcal path, we have to find the early start, early finish , latest start and latest finish of the activities.
early start of A = 0
early finish of A = early start + activity time
early finish of A = 0 + 5 ( 5)
early start of B = early finish of A ( 5)
early finish of B = 5 + 4 ( 9)
early start of C = early finish of B ( 9)
early finish of C = 9 + 3 ( 12)
early start of D = early finish of c ( 12)
early finish of D = 12 + 4 ( 16)
early start of e = early finish of C ( 12)
early finish of e = 12 + 9 ( 21)
early start of f = early finish of c ( 12)
early finish of f = 12 + 6 (18)
early start of g = early finish of f ( 18)
early finish of g = 18 + 2 ( 20)
early start of H = maximum ( early finish of D,E,G) 21
early finish of H = 21 +4 ( 25)
To find the backward pass
Latest finish of H = 21 +4 ( 25)
Latest start of H = 25 – 4 ( 21)
Latest finish of g = latest start of H ( 21)
latest start of g = 21 – 2 ( 19)
Latest finish of f = latest start of g ( 19)
latest start of f = 19 – 6 ( 12)
Latest finish of E = Latest start of H ( 21 )
latest start of E = 21 – 9 ( 12)
latest finish of D = latest start of h ( 21)
latest start of D = 21 – 4 ( 17)
latest finish of C = minimum latest start of ( D,E,F) 12
latest start of C = 12 – 3 ( 9)
latest finish of B = latest start of c( 9)
latest start of B = 9 – 4 ( 5)
latest finish of A = latest start of b(5)
latest start of A = 5 – 5 ( 0)
The slack of each activity is calculated as the difference between latest start and early start
Activity |
Activity time |
Immediate predecessor |
Early start |
Early finish |
latest start |
Latest finish |
Slack |
A |
5 |
_ |
0 |
5 |
0 |
5 |
0 |
B |
4 |
A |
5 |
9 |
5 |
9 |
0 |
C |
3 |
B |
9 |
12 |
9 |
12 |
0 |
D |
4 |
C |
12 |
16 |
17 |
21 |
5 |
E |
9 |
C |
12 |
21 |
12 |
21 |
0 |
F |
6 |
C |
12 |
18 |
13 |
19 |
1 |
G |
2 |
F |
18 |
20 |
19 |
21 |
1 |
H |
4 |
D,E,G |
21 |
25 |
21 |
25 |
0 |
The critical path is A-B-C-E-H because the slack is zero
The project duration is the sum of the activities on the critical path i.e. = 5 +4 + 3 + 9 + 4
Project duration = 25
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C) The slack of each activity is shown in the table below
Activity |
Activity time |
Immediate predecessor |
Early start |
Early finish |
latest start |
Latest finish |
Slack |
A |
5 |
_ |
0 |
5 |
0 |
5 |
0 |
B |
4 |
A |
5 |
9 |
5 |
9 |
0 |
C |
3 |
B |
9 |
12 |
9 |
12 |
0 |
D |
4 |
C |
12 |
16 |
17 |
21 |
5 |
E |
9 |
C |
12 |
21 |
12 |
21 |
0 |
F |
6 |
C |
12 |
18 |
13 |
19 |
1 |
G |
2 |
F |
18 |
20 |
19 |
21 |
1 |
H |
4 |
D,E,G |
21 |
25 |
21 |
25 |
0 |