Please use java. Thank You
Make a program as follows: Define 2D char array (5 by 5) and initialize with asterisk mark. Repeatedly display the array using while loop. In each iteration of the while loop, user inputs two numbers as a y x coordinate (row and column index), then display@ on the coordinate If the row and column index user inputs are out of array bound, the while loop is terminated.
Tested on Eclipse
/***************************************AsteriskParamid.java*********************************/
import java.util.Scanner;
/**
* The Class AsteriskParamid.
*/
public class AsteriskParamid {
/**
* Display.
*
* @param arr the arr
*/
public static void display(char[][] arr) {
for (int i = 0; i < arr.length; i++) {
for (int j = 0; j < arr[0].length; j++) {
System.out.print(arr[i][j]);
}
System.out.println();
}
}
/**
* The main method.
*
* @param args the arguments
*/
public static void main(String[] args) {
int rows = 5;
int cols = 5;
Scanner input = new Scanner(System.in);
char[][] arr = new char[rows][cols];
// adding asterisk into 2d array
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
arr[i][j] = ‘*’;
}
}
System.out.println(“============Printing Asterisk paramid============”);
display(arr);
//printing @ at given index
for(int i=0;i<rows;i++){
System.out.println(“Please Enter Y cordinate”);
int yCord = input.nextInt();
System.out.println(“Please Enter X cordinate”);
int xCord = input.nextInt();
for(int j=0;j<cols;j++){
if(yCord>=rows || xCord>=cols) {
System.out.println(“Out of bound. Terminating the loop”);
return;
}else if(yCord==i && xCord == j){
System.out.print(“@”);
}else{
System.out.print(“*”);
}
}
System.out.println();
}
}
}
/**********************output***********************/
============Printing Asterisk paramid============
*****
*****
*****
*****
*****
Please Enter Y cordinate
0
Please Enter X cordinate
3
***@*
Please Enter Y cordinate
1
Please Enter X cordinate
1
*@***
Please Enter Y cordinate
5
Please Enter X cordinate
0
Out of bound. Terminating the loop
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