# (Solved Homework): (a) Derive the operation count for the function F() below, assuming the worst case scenario. Show all the necessary details. void F (flo…

(a) Derive the operation count for the function F() below, assuming the worst case scenario. Show all the necessary details. void F (float [], int n) { // args: array v[] of size n int i: float x: for(int j = 1: j x && i > = 0) {v[i + 1] = v[i]: i = i – 1: } v[i + 1] = x: }}

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In the function, the outer loop is running for n times and the inner loop is running for 1 to jth number of outer iteration (in the worst case).

So for j = 1   the inner loop runs for 1 time   (worst case)
= 2   the inner loop runs for 2 time

=n    the inner loop runs for n

Total complexity will be 1 +2 + 3+….+n = n(n+1)/2
So it is O(n^2)

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