(Solved Homework): a. Create an object that stores the value 3^2 times 4^1/8. b. Overwrite your object in (a) by…

Using the R langauge answer the following questions.

Exercise 2.2 Create an object that stores the value 32 × 41 /8 a. b. Overwrite your object in (a) by itself divided by 2.33. Print the result to the console. c. Create a new object with the value -8.2x 10-13. d. Print directly to the console the result of multiplying (b) by (c).

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a. Create an object that stores the value 3^2 times 4^1/8. b. Overwrite your object in (a) by itself divided by 2.33. Print the result to the console. c. Create a new object with the value -8.2 times 10^-13. d. Print directly to the console the result of multiplying (b) by (c).

Expert Answer

Explanation ::

  • Code in R langauge is given below along with output.
  • Please read all the comments for better understanding of the code.
  • To get power function in R, two asterix are used. For example suppose we need 512 then we should write 5**12 to get the required value.
  • Rest calculation are easy i.e multiplication and division.
  • Still check out the brackets used in code for proper calculations.

Code in R language::

Code screenshot::

Code in Text::

# a is object that stores the required value.
# Power is calculated using two asterix(**)
# Suppose we want 3^2 then we write 3**2
a <- (3**2)*(4**(1/8))

# object a is divided by 2.33 and value is stored in object a itself.
a <- a/2.33

#Now we print the object a to console.
print(a)

# Creating new object named newObject that stores the value given in question
newObject <- (-8.2)*(10**(-13))

# Now we have values in objects a and newObject respectively.
# As required both objects are mutiplied and printed to the console.
print(a*newObject)

Output::

Screenshot::

Text::

> # a is object that stores the required value.
> # Power is calculated using two asterix(**)
> # Suppose we want 3^2 then we write 3**2
> a <- (3**2)*(4**(1/8))
>
> # object a is divided by 2.33 and value is stored in object a itself.
> a <- a/2.33
>
> #Now we print the object a to console.
> print(a)
[1] 4.593504
>
> # Creating new object named newObject that stores the value given in question
> newObject <- (-8.2)*(10**(-13))
>
> # Now we have values in objects a and newObject respectively.
> # As required both objects are mutiplied and printed to the console.
> print(a*newObject)
[1] -3.766673e-12

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